2[t-(4t+8)+4]=2(t+4)

Solution for 2[t-(4t+8)+4]=2(t+4) equation:

Simplifying
2[t + -1(4t + 8) + 4] = 2(t + 4)

Reorder the terms:
2[t + -1(8 + 4t) + 4] = 2(t + 4)
2[t + (8 * -1 + 4t * -1) + 4] = 2(t + 4)
2[t + (-8 + -4t) + 4] = 2(t + 4)

Reorder the terms:
2[-8 + 4 + t + -4t] = 2(t + 4)

Combine like terms: -8 + 4 = -4
2[-4 + t + -4t] = 2(t + 4)

Combine like terms: t + -4t = -3t
2[-4 + -3t] = 2(t + 4)
[-4 * 2 + -3t * 2] = 2(t + 4)
[-8 + -6t] = 2(t + 4)

Reorder the terms:
-8 + -6t = 2(4 + t)
-8 + -6t = (4 * 2 + t * 2)
-8 + -6t = (8 + 2t)

Solving
-8 + -6t = 8 + 2t

Solving for variable 't'.

Move all terms containing t to the left, all other terms to the right.

Add '-2t' to each side of the equation.
-8 + -6t + -2t = 8 + 2t + -2t

Combine like terms: -6t + -2t = -8t
-8 + -8t = 8 + 2t + -2t

Combine like terms: 2t + -2t = 0
-8 + -8t = 8 + 0
-8 + -8t = 8

Add '8' to each side of the equation.
-8 + 8 + -8t = 8 + 8

Combine like terms: -8 + 8 = 0
0 + -8t = 8 + 8
-8t = 8 + 8

Combine like terms: 8 + 8 = 16
-8t = 16

Divide each side by '-8'.
t = -2

Simplifying
t = -2